8% of items in a shipment are known to be defective. if a sample of 5 items is randomly selected from this shipment, what is the probability that at least one defective item will be observed in this sample? round your result to 2 significant places after the decimal (for example, 0.86732 should be entered as 0.87).

0.34

Step-by-step explanation:

Given : The proportion of  items in a shipment are known to be defective : p=0.08

Number of items selected = 5

By using binomial probability distribution formula,  the probability of getting success in x trials is given by :-

Now, the probability that at least one defective item will be observed in this sample will be :-

Hence, the probability that at least one defective item will be observed in this sample is 0.34

(0, 4)

Step-by-step explanation:

The y-intercept is where the graph crosses the y-axis when x = 0. Since you are given the graph, you can see that when x = 0, the graph crosses y = 4, so our y-int is (0, 4).