8. solve the system using substitution. show all work. (3 points)
y = -2x + 6
3y - x + 3 = 0
if someone could give me a full explanation of this by tomorrow i'd greatly 'ppreciate it

Ok. first you have to pick x or y or whatever variable you have and the number multiplied with it has to be the same in each equation but one has to be positive and one negative.
lets pick x

y=-2x+6
3y=x-3/ *2

so the x are positive and negative we have to multiply the equation with 2

y=-2x+6
6y=2x-6

now you have to add the equations. you do that by adding each side of the equatins together like this:

y+6y=-2x+6+2x-6 the x will cancel out

7y=0
y=0

now just go back to one of the previous equations and put the y in it.

0=-2x+6
2x=6
x=3

here you go

Step-by-step explanation:

you would solve by grouping the first two terms together and the last two terms together. (x^3+x^2)(+(4x+4)=0. you would factor each one and get x^2(x+1)+ 4(x+1)=0. the final outcome is (x^2+4)(x+1)=0. this is how you find the roots of this equation

sorry if this answer is wrong