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laureanogabriel
18.10.2019 •
Mathematics
9. a rectangle has a width that is 2 feet longer than four times the length. what is the length of the rectangle
if the perimeter is 64 feet? (hint: draw a picture and use algebra to solve)
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Ответ:
6 feet
Step-by-step explanation:
Perimeter = 2L + 2W
Since you know the perimeter is 64 feet, you would plug that into the perimeter side.
64 = 2L + 2W
You also know the width is 2 feet longer than 4 times the length.
64 = 2L + 2(2 + 4L) > Multiply 2 * 2 and 2 * 4l
64 = 2L + 4 + 8L > Subtract 4 from each side
-4 -4
60 = 2L + 8l > add these two
60 = 10L
/10 /10 > divide by 10 on each side
6 = L
Now that we know the length, find the width.
64 = 2(6) + 2(2 + 4(6)) > multiply 2 * 6 and 4 * 6
64 = 12 + 2(2 + 24) > add 24 and 2
64 = 12 + 2(26) > multiply 2 and 26
Before you go any further, you now know that the width is 26 feet. Continue solving.
64 = 12 + 52
64 = 64
Everything checks out.
The length is 6 feet and the width is 26 feet.
Ответ: