95% of students at school weigh between 62 kg and 90 kg. assuming this data is normally distributed, what are the mean and standard deviation?

We can calculate (62 + 90) / 2 = 76. it's known that 95% lies between the mean and twice the standard deviation. if the mean is "μ" and the standard deviation is "σ": μ-2σ and μ+2σ. if μ=76, then 76+2σ = 90, so 2σ = 14, so σ = 7.

the mean is 76 and the standard deviation 7. 

Mean is 76 and standard deviation is 7.

Step-by-step explanation:

Let be the mean and is the standard deviation of the given data,

Thus, 95% of the data lies between and

Now, 95% of students at school weigh between 62 kg and 90 kg,

So, the mean is,

The great thing about this problem is they give you everything you need to solve it easily. so the expression is: 12h+30w12h+30wand so everywhere you have an “h” you place 66. and everywhere you have a “w” you place 33. then the expression will look like this: 12(66)+30(33)12(66)+30(33)from here you multiply and then add. getting the following of: $785,862hope this