Mathematics: A 0.68 kg tennis ball is given an angular momentum of 2.72 X 10-3 kg.m2/s when struck by a racquet. If its radius of gyration is 2 cm what is its angular velocity? 50 POINT QUESTION!! Any help is appreciated, thank you!

A 0.68 kg tennis ball is given an angular momentum - id06813267824, tiggyandrep2dbee

Ответ:

mastershadow2018

15.06.2021

The angular velocity of the tennis ball is 10 radians per second.

Step-by-step explanation:

The tennis ball can be represented as a particle, the angular momentum (), in kilogram-square meter per second, of the tennis ball is described by the following formula:

$L = m\cdot r^{2}\cdot \omega$ (1)

Where:

- Mass of the tennis ball, in kilograms.

- Radius of gyration, in meters.

$\omega$ - Angular velocity, in radians per second.

If we know that $m = 0.68\,kg$ , $r = 0.02\,m$ and $L = 2.72\times 10^{-3}\,\frac{kg \cdot m^{2}}{s}$ , then the angular velocity of the tennis ball is: