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14.04.2021 •
Mathematics
A 10.0kg rock is dropped and hits the ground below at a speed of 60 m/s . Calculate the gravitational potential energy of the rock before it was dropped
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Ответ:
Solution:
Mass of body, m= 10kg
velocity, v= 60m/s
Now,kinetic energy on earth= potential energy at a that point [energy conservation]
so, kinetic energy= 1/2*m* v^2
= 1/2* 60(60)^2
= 30* 60*60
= 108000 joules
Ответ:
5/12
Step-by-step explanation:
Cause you find a way to get the same denominator