Mathematics: A = 3 and c = 12 c/a =

The exam scores are distributed normally with mean 72 and standard deviation 5.Recall the empirical (68 - 95 - 99.7) rule, which says that approximately 95% of a normal distribution lies within two standard deviations of the mean. Put another way,Also recall that the normal distribution is symmetric about its mean. This means thatFrom this last equation, it follows thatThat is, about 47.5% of the students scored between 72 and 87 on the exam....

A = 3 and c = 12 c/a = - id31211611474, jrbskso

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mariaaaaa69

02.03.2021

Mathematics

Step-by-step explanation:

a = 3 and c = 12 c/a =12/3=4

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Ответ:

amandafutch24

02.03.2021

Mathematics

4, because 12/3 is 4 cause 3×4=12

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jadenjohnson89

04.07.2020

Mathematics

The exam scores are distributed normally with mean 72 and standard deviation 5.
Recall the empirical (68 - 95 - 99.7) rule, which says that approximately 95% of a normal distribution lies within two standard deviations of the mean. Put another way,

$\mathbb P(|S-72|\le2\cdot5)=\mathbb P(-10\le S-72\le10)=\mathbb P(62\le S\le87)\approx0.95$

Also recall that the normal distribution is symmetric about its mean. This means that

$\mathbb P(|S-72|\le 5)=2\,\mathbb P(0\le S-72\le 5)=2\,\mathbb P(72\le S\le77)\approx0.95$

From this last equation, it follows that

$\mathbb P(72\le S\le 77)\approx\dfrac{0.95}2=0.475=47.5\%$

That is, about 47.5% of the students scored between 72 and 87 on the exam.

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A = 3 and c = 12 c/a =

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