laza87
07.01.2021 •
Mathematics
A 4-meter ladder is placed against a wall so
that it reaches a height of 3.7m. To the nearest
tenth of a meter, how far away from the base
of the wall are the feet of the ladder?
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Ответ:
1.5 meters.
Step-by-step explanation:
The ladder is 4 meters.
It reaches the height of 3.7 meters on a wall.
This creates a right angled triangle of hypotenuse (4 meters) and height (3.7 meters).
We are to find the base length.
Applying the Pythagorean theorem;
a² + b² = c² , where a is the base length, b is the height length and c is the hypotenuse length.
∴ a² = c² - b² = 4² - 3.7² = 2.31
a (base length) = = 1.519868415 meters
To round off the answer to the nearest tenth of a meter;
Tenth of a meter = × 1 meter = 0.1 meters
So we're rounding off the answer to one decimal place.
I.e 1.519868415 meters = 1.5 meters (rounded off to the nearest tenth of a meter.
Ответ:
The answer would be 240
Step-by-step explanation:
you would round all of the numbers then add them together and then subtract by 180 and get 24 or 240