A 40cm length of wire is used to form a rectangle. The width of the rectangle is 2cm longer than the height.
What is the length of the shortest side?

9cm

Step-by-step explanation:

to solve first divide the total perimiter (40cm)  by 4

this would allow 10cm for each side to allow the longer side to be 2 cm longer than the height we must subtract 1cm (for a total of 2cm) from each side of the rectangle, this would result in the shorter side having a length of 9cm

40=2 x (9+11)

1.57ft²

Explanation:

A=πr²

d=2r

A=1/4πd²=1/4·π·2² ≈ 3.14159ft²

Divide 3.141 by 2

1.57ft²