A, b and c are collinear and b is between a and c. the ratio of ab to ac is 1: 3. if a is at (2,-6) and b is at (3,-1) what are the coordinates of point c

The coordinate of C is (5,9)

Step-by-step explanation:

A, B and C are collinear and B is between A and C.

The ratio of AB to AC is 1:3

If A is at (2,-6) and B is at (3,-1)

AB:AC = 1:3

B is between A and C

AB:(AB+BC) = 1:(1+2)

Therefore, AB:BC = 1:2

Let the point C (a,b)

Using section formula:

where,

Substitute into formula and solve coordinate point C

Hence, The coordinate of C is (5,9)

(5, 9)

Step-by-step explanation:

The distance between A and B is 1/3 the distance between A and C.

x coordinates:

3 − 2 = 1/3 (x − 2)

1 = 1/3 (x − 2)

3 = x − 2

x = 5

y coordinates:

-1 − (-6) = 1/3 (y − (-6))

5 = 1/3 (y + 6)

15 = y + 6

y = 9

The coordinates of point C are (5, 9).

B) Angle 2 and Angle 3

Step-by-step explanation:

Angle 2 and Angle 3 are equal since they're vertical angles and aren't supplementary

Angle 7 and 8 are supplementary

Angle 1 and 7 are supplementary

Honestly, i have no clue with angle 4 and angle 4. I just know that vertical angles aren't supplementary because they're equal to each other so I'll assume this is the case as well.