Mathematics: A body of mass 2 kg moves in a (counterclockwise) circular path of radius 3 meters, making one revolution every 5 seconds. You may assume the circle is in the xy-plane, and so you may ignore the third component. A. Compute the centripetal force acting on the body. B. Compute the magnitude of that force.

224Step-by-step explanation:...

A body of mass 2 kg moves in a (counterclockwise)

zahriamarie10

20.03.2021

a) $\vec{F_{c}}=mR\omega^{2}$

$\vec{F_{c}}=9.53 \: N \vec{r}$

b) $|\vec{F_{c}}|=9.53 \: N$

Step-by-step explanation:

a) The centripetal force equation is:

$\vec{F_{c}}=m\vec{a_{c}}$

$\vec{F_{c}}=mR\omega^{2}$

Now, we know that the body makes one revolution every 5 seconds, so we can find the angular velocity:

$\omega=\frac{1 rev}{5 s}=0.2\: \frac{rev}{s}=1.26\: \frac{rad}{s}$

$\vec{F_{c}}=2*3*1.26^{2}=9.53 \: N \vec{r}$

The centripetal force is a vector in the radius direction.

b) The magnitude of that force will be:

$|\vec{F_{c}}|=9.53 \: N$

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