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RealStephani
26.08.2020 •
Mathematics
A box contains $7.45 in nickels, dimes, and quarters. There are 43 coins in all, and the sum of the numbers of nickels and dimes is 3 less than the number of quarters. How many coins of each kind are there?
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Ответ:
Number of nickels = 6
Number of dimes = 14
Number of quarters = 23
Step-by-step explanation:
Total number of coins = 43
Let number of nickels = n
Let number of dimes = d
Let number of quarters = q
Money in n nickels =![n \times 0.05](/tpl/images/0729/3482/33ef4.png)
Money in d dimes =![d \times 0.10](/tpl/images/0729/3482/86d84.png)
Money in q quarters =![q \times 0.25](/tpl/images/0729/3482/28dce.png)
Total money = $7.45
The sum of the numbers of nickels and dimes is 3 less than the number of quarters.
i.e.
Let us put the value in (1):
Putting the value of q in (1) and (2):
n+d = 20 .... (3)
(4) - (3):
d = 14
Now, from (3):
n = 6
Number of nickels = 6
Number of dimes = 14
Number of quarters = 23
Ответ:
price is $2.50
This is a 250% increase.
If it costs $1.25 to make...
250% of $1.25 = $1.25 × 2.50 = $3.125 for the new price if we want to keep that 250% increase. Since there is no half cent, we round up to $3.13.
To maintain the gross margin percentage, we would have to up the unit selling price 63¢ to $3.13.