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tilacohen
02.09.2020 •
Mathematics
A car of m = 1200. kg collides with a tree while traveling 60.0 mph. The collision occurs over a time period of 0.0500 seconds. Determine the magnitude of the force exerted on the car as it comes to rest during the collision. (1 m/s = 2.24 mph) 1.58 × 10 3N 1.44 × 10 6N 3.60 × 10 3N 6.4331 × 10 5N
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Ответ:
6.4331 × 10 5N
Step-by-step explanation:
Given the following :
Mass (m) of car = 1200kg
Initial Velocity (u) of car = 60 mph
Final velocity = 0 ( comes to rest)
Velocity in m/s = 60 / 2.24 = 26.785 m/s
Time (t) = 0.0500
Using the relation :
Ft = m(v - u)
Where,
v = final velocity ; u = initial velocity ; t = time ; F = force
F*0.05 = 1200(26.785 - 0)
0.05F = 32142.86 - 0
F = 32142.86 / 0.05
F = 642857.14 N
F = 6.43 × 10^5 N
Ответ:
Cot(a)=cos(a) / sin(a)
Cos(a)=5
Sin(a)=12
2sina-3cosa / 4sina-9cosa
2(12)-3(5) / 4(12)-9(5)
24-15 / 48-45
9/3
3