kkcheers16
19.01.2021 •
Mathematics
a cash register contains 165 coins consisting of pennies, nickles, and dimes. If the total number of nickels and dimes is equal to twice the number of pennies, and the total value of the coins is $7.95, find the number of each type of coin.
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Ответ:
The number of
Pennies = 55 coins
Dimes = 38 coins
Nickels = 72 coins
Step-by-step explanation:
A penny is worth 1 cent. = 0.01p
A nickel is worth 5 cents = 0.05n
A dime is worth 10 cents = 0.10d
A cash register contains 165 coins consisting of pennies, nickels and dimes.
p + n + d = 165 coins
If the total number of nickels and dimes is equal to twice the number of pennies
n + d = 2p
We substitute
2p for n + d
p + n + d = 165 coins
p + 2p = 165
3p = 165
p = 165/3
p = 55 coins
n + d = 2p
n + d = 2(55)
n + d = 110
n = 110 - d
The total value of the coins is $7.95
0.01p + 0.05n + 0.10d = $7.95
We substitute
p = 55
n = 110 - d
0.01(55) + 0.05(110 - d) + 0.10d = 7.95
0.55 + 5.5 - 0.05d + 0.10d = 7.95
6.05 + 0.05d = 7.95
Collect like terms
0.05d = 7.95 - 6.05
0.05d = 1.9
d= 1.9/0.05
d = 38 coins
n = 110 - d
n = 110 - 38
n = 72 coins
The number of
Pennies = 55 coins
Dimes = 38 coins
Nickels = 72 coins
Ответ: