christyr2002
27.01.2021 •
Mathematics
A certain statistic will be used as an unbiased estimator of a parameter. Let R represent the sampling distribution of the estimator for samples of size 35, and let S represent the sampling distribution of the estimator for samples of size 15. Which of the following must be true about R and S?
a. The expected values of R and S will be equal, and the variability of R will be less than the variability of S.
b. The expected values of R and S will be equal, and the variability of R will be equal to the variability of S.
c. The expected values of R and S will be equal, and the variability of R will be greater than the variability of S.
d. The expected value of R will be greater than the expected value of S, and the variability of R will be greater than the variability of S.
e. The expected value of R will be greater than the expected value of S, and the variability of R will be less than the variability of S.
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Ответ:
Using the Central Limit Theorem, it is found that the correct option is:
a. The expected values of R and S will be equal, and the variability of R will be less than the variability of S.Central Limit Theorem The Central Limit Theorem establishes that, for a normally distributed random variable X, with meanIn this problem:
The samples are taken from the same population, hence they have the same expected value.Due to the higher sample size, R has less variability.Hence, option A is correct.To learn more about the Central Limit Theorem, you can take a look at link
Ответ:
c. The expected values of R and S will be equal, and the variability of R will be greater than the variability of S.
Step-by-step explanation:
This is Central Limit Theorem concept in which independent variables are added and form a normal distribution. The random sample of n sample size is selected which calculates normally distributed mean and variance. The expected value of samples distributor will be higher than the sample distribution.
Ответ:
32
Step-by-step explanation:
3x+1=8x-24
25=5x
x=5
3 times 5 plus 1 is 16 and so the length is 32
comment section:
XM=MY because MN is segment bisector
XM=3x+1=3*5+1=16=MY and since XM+MY=XY 16+16=32