Mathematics: A clown is shot out of cannon with a velocity of 200 feet per second at an angle of 24° with the horizontal. Find the vertical and horizontal components of the velocity of this clown.

A clown is shot out of cannon with a velocity

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26.01.2022

Vertical component of velocity is 81.35 ft/sec.

Horizontal component of velocity is 182.6 ft/sec .

Step-by-step explanation:

Horizontal component of velocity is defined as:

$v_{x} = v\times cos\theta$

Vertical component of velocity is defined as:

$v_{y} = v\times sin\theta$

Where $v_{x} , v_{y}$ are the horizontal and vertical components of velocity.

is the actual velocity and

$\theta$ is the angle with horizontal axis at which the object was thrown.

Here, we are provided with the following:

v = 200 ft/sec

$\theta = 24^\circ$

$v_{x} = 200 \times cos24^\circ\\\Rightarrow 200 \times 0.913\\\Rightarrow v_{x} = 182.6 ft/sec$

$v_{y} = 200 \times sin24^\circ\\\Rightarrow 200 \times 0.407\\\Rightarrow v_{y} = 81.35 ft/sec$

So, Vertical component of velocity is 81.35 ft/sec.

Horizontal component of velocity is 182.6 ft/sec .

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