A coin is tossed, and a die is rolled. Find the probability of landing on the tail side of the coin and rolling a 1 on the die?

Probability[Tail side of coin and rolling 1 on die] = 1/12

Step-by-step explanation:

Given:

Coin tossed

Die roll

Find:

Probability[Tail side of coin and rolling 1 on die]

Computation:

Probability of an event = Favorable outcome / Total outcomes

Probability of getting tail on coin = 1 / 2

Probability of getting 1 on die = 1 /6

P[A and B] = P(A) x P(B)

Probability[Tail side of coin and rolling 1 on die] = Probability of getting tail on coin x Probability of getting 1 on die

Probability[Tail side of coin and rolling 1 on die] = [1/2][1/6]

Probability[Tail side of coin and rolling 1 on die] = 1/12

^^^WRONG it says explain why its wrong not correct it

the CORRECT answer would be

No, the simplification is not correct.

Cosecant is the reciprocal of sine, not cosine.

Secant is the reciprocal of cosine, not sine.

The given expression simplifies to cot(t).

The identical answer, you are welcome!

Hope this helps, if so give me a thanks please