A coin jar contains 10 quarters, 6 dimes and 8 nickels. Find the probability that two quarters are chosen random from the jar.

0.1630

Step-by-step explanation:

Number of quarters = 10

Number of dimes = 6

Number of nickels = 8

Total number = 10+6+8 = 24

Probability of choosing the first quarter will be: = Number of quarters/Total number of money

= 10/24 = 5/12

Since a quarter has been selected, the total number will reduce to 23 the next time a quarter is choosing and the number of quarters will now be 9. Therefore, the probability of choosing the second quarter will be: = 9/23

Therefore, the probability that two quarters are chosen random from the jar will be:

= 5/12 × 9/23

= 45/276

= 0.1630

Let Y be the number of compact cars and 20 - Y be the number of full-sized car. If the total cost of 20 cars is $372, 000. Then we have: (Cost of compact car * number of compact car)+ (cost of full-sized car * number of full-sized car). So we have (15, 000 * Y) + (23, 000 * (20 -Y)) = 372, 000. Multiplying the expression, we have; 15, 000Y + 460, 000 - 23000Y = 372, 000. 15000Y - 23000Y = 372, 000 - 460, 000. -8000Y = - 88, 000. Hence Y = 11. Hence 11 compact cars were bought.