A coin placed below a rectangular glass prism of thickness 7.5cm and refractive index 1.5 is viewed vertically above the glass. Calculate the apparent displacement of the coin.

The apparent displacement of the coin is 2.5 cm

Step-by-step explanation:

Mathematically;

shift = real depth * (1-1/refractive index)

From the question;

real depth = 7.5 cm and refractive index = 1.5

Thus, substituting this, we have;

shift = 7.5 * (1-1/1.5)

shift = 7.5 * (1/3)

shift = 7.5/3 = 2.5 cm

See below

Step-by-step explanation:

Given points:

3, 2.25,  opposite of 4, -(-1 1/2) ⇒ 3, 2.25, -4, 1 1/2

In ascending order:

-4, 1.5, 2,25, 3

Using o,25 intervals:

-4.00, -3.75, --3.50, -3.25, -3.00, -2.75, -2.50, -2.25, -2.00, -1.75, -1.50, -1.25, -1.00, -0.75, -0.50, -0.25, 0, 0.25, 0.50, 0.75, 1.00, 1.25, 1.50, 1.75, 2.00, 2.25, 2.50, 2.75, 3.00

Plotted tick marks

-4.00, 1.50, 2.25, 3.00

Number of marks

between: -4.00 and 1.50 = 21between: 1.50 and 2.25 = 2between: 2.25 and 3.00 = 2