A company determines that monthly sales S(t), in thousands of dollars, after t months of marketing a product is given by S(t)equals2 t cubed minus 45 t squared plus 180 t plus 130. a) Find Upper S prime(1), Upper S prime(2), and Upper S prime(4). b) Find Upper S double prime(1), Upper S double prime(2), and Upper S double prime(4). c) Interpret the meaning of your answers to parts (a) and (b).

a) S'(1) = 136; S'(2) = 104; S'(4) = 76;

b) S''(1) = -38; S''(2) = -26; S''(4) = -2

Step-by-step explanation:

a) S' means first derivative;

(6t³ - 45t² +180t +130) = 6t² - 50t + 180

S'(1) = 6.1² - 50.1 + 180

S'(1) = 136

S'(2) = 6.2² - 50.2 + 180

S'(2) = 104

S'(4) = 6.4² - 50.4 + 180

S'(4) = 76

b) S'' is the second derivative of S:

(6t² - 50t + 180) = 12t - 50

S''(1) = 12.1 - 50

S''(1) = -38

S''(2) = 12.2 - 50

S"(2) = -26

S"(4) = 12.6 - 50

S"(4) = -2

c) Derivative is the rate of change of a function. The first derivative is the slope of the tangent line to the graph if the function in a determined point, while the second derivative measures how the rate of change is changing.

Analysing the values, we can conclude that the sales of the product after t months is decreasing at a rate of 12.

Percent of discount = percent of change
change in price = $120 - $90 = $30
so percentage of change = change / original amount multiplied by hundred

in short change / original value × 100
= 30 / 120 ×100
= 1 / 4 × 100
= 25 %

HOPE IT HELPED !!!