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evelyn82
24.03.2020 •
Mathematics
A cone of volume 54π is cut by a plane parallel to the base, 1/3 of the way up the height of the cone (from the base). Find the volume of the resulting frustum.
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Ответ:
Correct Vf = 38 π
Step-by-step explanation:
Given:
Vc = 54 π
The ratio of the height of the cone and the height of the frustum is:
Hc : Hf = 3 : 1 ⇒ Hc = 3 · Hf
The ratio of the radius R of the base of the cone to the radius r of the upper base of the frustum is:
R : r = Hc : (Hc - Hf) ⇒ R : r = (3· Hf) : (3 · Hf - Hf) ⇒ R : r = 3 · Hf : 2 · Hf
R : r = 3 : 2 ⇒ r = (2/3) · R
The formula for calculating the volume of a cone is:
Vc = (R² · π · Hc) / 3 = (R² · π · 3 · Hf) / 3 = R² · π · Hf
The formula for calculating the volume of a frustum is:
Vf = (π · Hf · (R² + R · r + r²)) / 3 = (π · Hf · (R² + R · (2/3) · R + ((2/3) R)²)) / 3
Vf = (π · Hf · (R² + (2/3) ·R² + (4/9) · R²)) / 3 ⇒
Vf = (π · Hf · ( (9/9)R² + (6/9) ·R² + (4/9) · R²)) / 3 ⇒
Vf = (π · Hf · (19/9) · R²) / 3 = (19/27) · R² · π · Hf
Vc / Vf = (R² · π · Hf) / ((19/27) · R² · π · Hf)
R², π and Hf were shortened and we get:
Vc / Vf = 27 / 19 ⇒ Vf = (19 · Vc) / 27 ⇒
Vf = 19 · 54 · π / 27 = 38 π
Vf = 38 π
God is with you!!!
Ответ:
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Step-by-step explanation: