A dart is tossed and hits the dart board shown. The dart is equally likely to land on any point on the dart board. Find the probability that the dart lands in the center region.

x=9

step-by-step explanation:

according to the statement the product of   a + 3 and –2a2 + 15a + 6 is –2a3 + xa2 + 51a + 18.

lets find the product by yourself then solve the question:

(a++15a+6)

multiply each value of bracket 1 by   bracket 2

a(-2a^2+15a+6)+3(-2a^2+15a+6)

-2a^3+15a^2+6a-6a^2+45a+18

now combine the like terms:

-2a^3+9a^251a+18

it is given in the question that the product of   a + 3 and –2a2 + 15a + 6 =       –2a3 + xa2 + 51a + 18.

now compare the both expessions:

-2a^3+9a^251a+18 = –2a3 + xa2 + 51a + 18.

on comparing both sides you will notice that the second term on l.h.s is 9a^2 and the second term on r.h.s is xa^2

therefore x = 9