A directed line segment begins at F(-8, -2), ends

Ответ:

edson23

19.04.2022

Mathematics

Given:

A directed line segment begins at F(-8, -2), ends at H(8, 6), and is divided in the ratio 8 to 2 by G.

To find:

The coordinates of point G.

Solution:

Section formula: If a point divide a line segment with end points (x_1,y_1) and (x_2,y_2) in m:n, then the coordinates of that point are

$Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)$

Point G divide the line segment FH in 8:2. Using section formula, we get

$G=\left(\dfrac{8(8)+2(-8)}{8+2},\dfrac{8(6)+2(-2)}{8+2}\right)$

$G=\left(\dfrac{64-16}{10},\dfrac{48-4}{10}\right)$

$G=\left(\dfrac{48}{10},\dfrac{44}{10}\right)$

$G=\left(4.8,4.4\right)$

Therefore, the coordinates of point G are (4.8, 4.4).

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Ответ:

Dmgirl123

04.05.2021

Mathematics

$\frac{\sqrt{2} }{6}$

Step-by-step explanation

$\frac{1}{\sqrt{18} } \\\frac{1}{\sqrt{18} } *\frac{\sqrt{18} }{\sqrt{18} } \\\frac{1*\sqrt{18} }{(\sqrt{18} )^2} \\\frac{1\sqrt{18} }{18} \\\frac{3\sqrt{2} }{18} \\\frac{\sqrt{2} }{6}$

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A directed line segment begins at F(-8, -2), ends at H(8, 6), and is divided in the ratio 8 to 2 by G. What are the coordinates of G?

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