Mathematics: A fan oscillates 250* and can be felt from a distance of 4 feet away . To the nearest tenth what area of the room can feel the wind from the fan? Use 3.14 for pi .

If she used rounding she would’ve gotten -25×10 equals -250...

A fan oscillates 250* and can be felt from a distance

bree249

11.06.2021

A=256.67ft^2

Step-by-step explanation:

From the question we are told that:

Fan oscillates $\theta=250$

Distance $d=Raduis\ r=4 feet$

Since

$250\textdegree =180\textdegree +70\textdegree$

Generally the equation for the area A is mathematically given by

$Area=Area\ of\ semi\ circle\ + area\ of\ 70\textdegree sector$

$A=A_{sm}+A_{70\textdegree}$

Where

$A_{sm}=\frac{1}{2} \pi r^2$

$A_{sm}=\frac{1}{2} 3.14 4^2$

$A_{sm}=25.12ft^2$

$A_{70\textdegree}=\frac{1}{2}r^2 \frac{70\textdegree}{360\textdegree}$

$A_{70\textdegree}=\frac{1}{2}*4^2* \frac{70\textdegree}{360\textdegree}$

$A_{70\textdegree}=1.55ft^2$

Therefore the area A is given as

$A=A_{sm}+A_{70\textdegree}$

A=25.12ft^2+1.55ft^2

A=256.67ft^2

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