(a) Find the term in 1/x^3 in the expansion of (3/x-2)^10

(b)
Using the information from part (a), find the term independent of x in the
expansion of (5x^3-7)(3/x-2)^10

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Ответ:

blink182lovgabbie

09.06.2021

Mathematics

Both

Kinetic energy is 25 joule

Potential energy is 784.8 joule

Step-by-step explanation:

Given : A 2-kg bowling ball rolls at a speed of 5 m/s on the roof of the building that is 40 tall.

To find : Is it KE or GPE or Both

Solution :

Mass of the ball - 2 kg

Velocity of the ball - 5 m/s

Height - 40 tall

Both the energy is applied on the object.

1) Kinetic energy (KE)

Formula to find KE is $KE=\frac{1}{2}mv^2$

$KE=\frac{1}{2}(2)(5)^2$

KE=25

Kinetic energy is 25 joule.

2) Potential energy (GPE)

Formula to find GPE is PE=mgh

g is the acceleration due to gravity, g=9.81 m/s^2

PE=(2)(9.81)(40)

PE=784.8

Potential energy is 784.8 joule.

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(a) Find the term in 1/x^3 in the expansion of (3/x-2)^10(b)Using the information from part (a), find the term independent of x in theexpansion of (5x^3-7)(3/x-2)^10