![evafaith](/avatars/46961.jpg)
evafaith
20.06.2020 •
Mathematics
A group of four components is known to contain two defectives. An inspector tests the components one at a time until the two defectives are located. Once she locates the two defectives, she stops testing, but the second defective is tested to ensure accuracy. Let Y denote the number of the test on which the second defective is found. Find the probability distribution for Y. (Enter your probabilities as fractions.)
Solved
Show answers
More tips
- H Health and Medicine Novomin: What is it and how to use it?...
- P Philosophy Unbelievable stories of encounters with otherworldly forces...
- L Leisure and Entertainment How to Choose the Perfect Gift for Men on February 23rd?...
- H Health and Medicine How to Treat Whooping Cough in Children?...
- H Health and Medicine Simple Ways to Lower Cholesterol in the Blood: Tips and Tricks...
- O Other How to Choose the Best Answer to Your Question on The Grand Question ?...
- L Leisure and Entertainment History of International Women s Day: When Did the Celebration of March 8th Begin?...
- S Style and Beauty Intimate Haircut: The Reasons, Popularity, and Risks...
- A Art and Culture When Will Eurovision 2011 Take Place?...
- S Style and Beauty How to Choose the Perfect Hair Straightener?...
Answers on questions: Mathematics
- M Mathematics A card is drawn from a stranded deck of cards find p(drawing a king or a club)...
- M Mathematics Please help me with this question....
- E English Which character from the outsiders says the following : —The sky was lighter in the east , and the horizon was a thin golden line. The clouds changed from gray to pink , and the mist...
- M Mathematics Kay is shown on the number line below what’s the process is best described as a value represented by point k...
- H History Which southeast asian country has a government that is now democratic but was once authoritarian? a. indonesia b. vietnam c. brunei d. laos...
Ответ:
Step-by-step explanation:
Let D stand for a defective unit,
G for a good unit.
Y can only be 2, 3, or 4.
P(Y=2):
Need to have D, D. There are 2 Ds of 4 total to start, then presuming the first was a D, there is 1 D of 3 total for the second choice.
P(Y=3):
Need to have D,G,D or G,D,D
So:
P(Y=2) = 1/6
P(Y=3) = 1/3
P(Y=4) = 1/2
P(Y=n) = 0 for all other values of n
Ответ: