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perlacruz0505
14.02.2020 •
Mathematics
A household refrigerator with a coefficient of performance of 2.4 removes energy from the refrigerated space at a rate of 600 Btu/h. Evaluating electricity at $0.08 per determine the cost of electricity in a month when the refrigerator operates for 360 hours
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Ответ:
$720
Step-by-step explanation:
Coefficient of performance of a refrigerator (COP) =![\frac{desired ouput}{Required inpu}](/tpl/images/0511/4989/f0733.png)
desired out i.e energy removed = 600Bth/hr
Required input=?
2.4=![\frac{600}{required inpu}](/tpl/images/0511/4989/00678.png)
required input=
=25Btu/hr
cost of electricity per hour = $0.08
cost of electricity for 360 hours =$0.08×360=$28.8
for an input of 25Btu/hr and 360 hours
∴cost of electricity in month =$28.8×25=$720
Ответ:
53.6%
Step-by-step explanation:
125 is 53.648086695% of 233