(a) How far is the right end of the rod (the point B) from the center of the wheel at time t=1/21 sec?
1+√13
(b) Express the x-coordinate of the right end of the rod as a function of t:
(2cos(7πt)+√16−4sin2(7πt),0) .
(c) Express the speed of the right end of the rod as a function of t:

B. 137.32 cm3

Step-by-step explanation:

So what we know is that

Height = 12

Diameter is 6 which would make the radius 3.

The current volume is 339.12

12cm × 1.12 = 12.44 (This is the new height.)

3cm × 1.12 = 3.36 9 (This is the new radius)

Volume of future can (V2) = πr²h = 3.14 × 3.36 ×3.36 × 13.44 = 476.43

Then you would subtract  476.43(new volume) - 339.12(old volume) = 137.31

That would round to 137.32 cm3.

So the answer is B. 137.32 cm3.