crosales102
06.10.2019 •
Mathematics
a is the midpoint of jm . if ja = 6x - 4 and jm = 9x + 13, find am.
the length of am is
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Ответ:
AM = 38
Step-by-step explanation:
Since A is the midpoint of JM, then
JA = AM = 6x - 4 , and
JA + AM = JM ← substitute values
6x - 4 + 6x - 4 = 9x + 13, that is
12x - 8 = 9x + 13 ( subtract 9x from both sides )
3x - 8 = 13 ( add 8 to both sides )
3x = 21 ( divide both sides by 3 )
x = 7
Hence
AM = 6x - 4 = (6 × 7) - 4 = 42 - 4 = 38
Ответ:
Step-by-step explanation:
Since A is the MIDPOINT of JM, AM is equivalent to JA, therefore you double up 6x - 4 and set that equal JM at 9x + 13:
-12x - 12x
______________________
−3x + 13 = −8
- 13 - 13
______________
−3x = −21
____ ____
−3 −3
[Plug this back into the equation of 6x - 4 to get the length of 38]
I am joyous to assist you anytime.
Ответ:
ugu
Step-by-step explanation: