A label prints in the pediatric pharmacy satellite for 500 mL of dextrose 15% solu-
tion. This concentration is not available
commercially and needs to be compound-
ed. Available in your pharmacy, you have
a 1 L bag of sterile water and a 1 L bag
of dextrose 70% available to compound
the solution. How many mLs of each are
needed to make the requested solution?

107.14 ml of 70% dextrose and 392.86 ml of sterile water should be used.

Step-by-step explanation:

Since a label prints in the pediatric pharmacy satellite for 500 mL of dextrose 15% solution, but this concentration is not available commercially and needs to be compounded, and available in your pharmacy, you have a 1 L bag of sterile water and a 1 L bag of dextrose 70% available to compound the solution, to determine how many mLs of each are needed to make the requested solution, the following calculation must be performed:

500 x 0.15 = 75

100 x 0.70 = 70

A x 0.70 = 75

A = 75 / 0.70

A = 107.14

Therefore, 107.14 ml of 70% dextrose and 392.86 ml of sterile water should be used.

The numerator has degree 1, and the denominator has degree 2. For large , the denominator will dominate, so the limit would be 0.

Put another way, we have

and each fraction with will aproach 0. The numerator itself approaches 0 while the denominator approaches 1, so the overall limit is 0.