A line has a slope of 2 and passes through the point (1,3) write an equation in slope intercept form

slope intercept form: y=

The answer to your question is  y = 2x + 1

Step-by-step explanation:

Data

slope = m = 2

Point = (1, 3)

Process

To solve this problem, just substitute the values in the equation slope-intercept form.

x1 = 1     y1 = 3

-Substitution

                    y - y1 = m(x - x1)

                    y - 3 = 2(x - 1)

-Expand

                    y - 3 = 2x - 2

-Simplify

                         y = 2x - 2 + 3

-Result

                         y = 2x + 1

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

You know:

m = 2       So substitute/plug it into the equation

y = mx + b

y = 2x + b     To find b, plug in the point (1, 3) into the equation, then isolate/get the variable "b" by itself in the equation

3 = 2(1) + b     Subtract 2 on both sides to get "b" by itself

3 - 2 = 2 - 2 + b

1 = b

y = 2x + 1

Answer and explanation:

Geometary software is merely a software implementation of solving the area of a triangle. Therefore geometry software employs all the methods used in coordinate algebra(manual) albeit behind the scenes, in the console of the software, and just displays the area in the screen after solving. While geometry software displays the area using automated methods in code, coordinate algebra solves area of the triangle manually using several steps. In both cases, we observe that algebra is required to solve area of the triangle as it is part of the algorithm used in the code for the geometry software. Also being able to use the geometry software requires that one understand coordinate algebra to be able to plot lines, points and planes at the correct locations on the screen and get desired result.