Mathematics: A line parallel to y=3/5x-3 and passing through the point (15,-2)

A line parallel to y=3/5x-3 and passing through

smashbrosfan777

21.01.2022

$\huge\boxed{y+2=\frac{3}{5}(x-15)}$

We will use point-slope form, where is the slope and (x_1,y_1) is a known point on the line.

y-y_1=m(x-x_1)

First, find the slope. Since the two lines will be parallel, they'll share the same slope of $\frac{3}{5}$ .

$y-y_1=\frac{3}{5}(x-x_1)$

Substitute in the known point.

$y-(-2)=\frac{3}{5}(x-15)$

Simplify the negative subtraction.

$\large\boxed{y+2=\frac{3}{5}(x-15)}$

Note: If you need the answer in a different form, please let me know below.

0,0(0 оценок)

sosa1k18

21.01.2022

y = $\frac{3}{5}$ x - 11

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = $\frac{3}{5}$ x - 3 ← is in slope- intercept form

with slope m = $\frac{3}{5}$

Parallel lines have equal slopes, thus

y = $\frac{3}{5}$ x + c ← is the partial equation of the parallel line

To find c substitute (15, - 2) into the partial equation

- 2 = 9 + c ⇒ c = - 2 - 9 = - 11

y = $\frac{3}{5}$ x - 11 ← equation of parallel line

0,0(0 оценок)

nculberson6

27.10.2021

angle Q,T,C, and B are right (90°)

angle D = R (from the sign)

angle E = S (from the sign)

0,0(0 оценок)