A line segment has the endpoints (-7, -4) and (9,8). What are the coordinates of the midpoint of this line segment?
A. (2, 4)
B.
(-1,2)
C. (-1,-6)
D.
(-8, 2)
E.
(-2,-4)
F.
(1, 2)

F

Step-by-step explanation:

to find x coordinate for midpoint, add both the x coordinates then divide by two. we get x=1

to find y coordinate for midpoint, add both the y coordinates then divide by two. we get y=2

so the coordinates of midpoint is (1,2), which is F

We have,  a. ortho (ab) = a.b - a.b/[a]² . /a/²

The /a/² cancel off each other, therefore,

a. ortho (ab) = a.b - a.b

a. ortho (ab) = 0

Therefore, the final result is 0.

Step-by-step explanation:

It should be noted that the orthogonal projection of a vector B onto A is given by a given formula known as:

proJ(ab)  = a.b/[a]² . a equation (1)

Where [a] is the magnitude of the vector a,

therefore, [a]² = a.a equation (2)

Which means that if we have a dot product between a vector and the sum of vector, it can be distributed to each vector.

That is : a . (c - d + b )

a.b - a.d + a.b equation (3)

and since it is given that Ortho (ab) = b - proJ(ab)equation (4)

and in order to show that a two vector are orthogonal, we need to show that their dot product is zero.

Where : a.b = /a//b/ cos ( Ф)

and if the dot product is zero (0), this will imply that ,

cos (Ф) = 0

Now moving forward to the proof,,

The first thing we do is substitute equation (1) into equation (4)

That will give us : ortho (ab) =  b - a.b/[a]² . a

and in order to show that vector a and orth(ab) are orthogonal, we need to show that their dot is zero

Therefore, a . ortho (ab) = a . b -  a.b/[a]² . a equation (5)

Now, substituting equation (2) into (5),

We have,  a. ortho (ab) = a.b - a.b/[a]² . /a/²

The /a/² cancel off each other, therefore,

a. ortho (ab) = a.b - a.b

a. ortho (ab) = 0

Therefore, the final result is 0.