A major corporation is building a 4,325-acre complex of homes, offices, stores, schools, and churches in the rural community of Glen Cove. As a result of this development, the planners have estimated that Glen Cove's population (in thousands) t years from now will be given by (25t2 + 150t + 100)/(t2 + 6t + 24)
A) Find the rate at which Glen Cove's population is changing with respect to time.
B) What will be the population after 10 years?
C) At what rate will the population be increasing when t = 10?

See explanation

Step-by-step explanation:

We have that;

P(t) = (25t2 + 150t + 100)/(t2 + 6t + 24)

a) rate at which Glen Cove's population is changing with respect to time.

dP/dt = (t^2 + 5t + 40) (50t + 125) - (25t^2 + 125t + 200) (2t + 5)/(t^2 + 5t + 40)^2

dP/dt = 1000t + 3000/(t^2 + 6t + 24)^2

b)  population after 10 years

P(t) = (25t2 + 150t + 100)/(t2 + 6t + 24)

P(t) =(25(10)^2 + 150(10) + 100)/((10^2 + 6(10) + 24)

P(t) = 4100/184

P(t) = 22283

c) when t = 10

dP/dt = 1000t + 3000/(t^2 + 6t + 24)^2

dP/dt = 1000(10) + 3000/(10^2 + 6(10) + 24)^2

dP/dt = 13000/33856

dP/dt = 0.384

B

x-10=3

 +10=+10

x=13

Step-by-step explanation:

I hope this helps