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laneake96
15.08.2020 •
Mathematics
A man buys a racehorse for $20,000 and enters it in two races. He plans to sell the horse afterward, hoping to make a profit. If the horse wins both races, its value will jump to $90,000. If it wins one of the races, it will be worth $55,000. If it loses both races, it will be worth only $15,000. The man believes there is a 30% chance that the horse will win the first race and a 40% chance that it will win the second one. Assuming that the two races are independent events, find the man's expected profit.
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Ответ:
Answer
$22400
Step by step Explanation
Cost of the racehorse = $20,000
value of racehorse if both races were won= $90,000
Value racehorse if one of the races were won=$55,000
Value of the racehorse if both races were lost= $15,000.
The probability of horse will win the first race is 0.30.
The probability that horse will win the second race is 0.40.
✓The probability of winning both the races is,
P(win both)= p(wining the first race) ×p(wining second race)
= 0.3×0.40
=0.12
√The probability of winning exactly one race is,
P(win one)= p(winning one race) p( not winning the other one)
0.3(1-0.4)+0.3(1-0.4)
=0.46
√The probability of losing both the races is,
[1-p(winning first race)] × [1-p(winning second race)]
=(1-0.4)(1-0.3)
=0.42
But we were to find the man’s expected profit, which can be calculated as;
[The probability of winning both the races×(value of racehorse if both races were won-Cost of the rracehorses)] +[The probability of winning exactly one race ×(Value racehorse if one of the races were won -Cost of the racehorse)] +[The probability of losing both the races ×(Value of the racehorse if both races were -cost of the race horse)]
0.12($90,000-$20,000)+0.46(55,000-20,000)+0.42(15,000-20,000)
=$22400
Therefore, the man’s expected profit is $22400
Ответ:
The Last One
Step-by-step explanation:
I used a special calculator plus, I did this already lol. Trust me <3