A man is 38 years old and his daughter is 14 years old. How many years will it be before the man's age is just twice that of
his daughter?
ver:
years

Step-by-step explanation

x+38=2(x+14)

The man is 38 and daughter is 14. They both will age in same years (x).

So, in how many years(x) will they both age until man is equal(=) to 2 times his daughters age?

x+ 38=2(x+14)

x+38=2x+ 28

10= x

In 10 years, the man will be 2twice as old as his daughter.

x = 50

Step-by-step explanation:

Exterior angle = interior angle + interior angle

120 = 70 + x

-70     -70

50 = x

x = 50