A man is twice as old as his son. Twelve years ago, the man was 3 times as old as his son. How old are the father and son
today?

Son's age = 24 years

Man's age = 48 years

Step-by-step explanation:

Let's take the age of son as x

Man's age = 2x

Twelve years ago,

Son's age= x-12

Man's age= 2x-12

Man is three times as old as his son so,

Solving for x,

2x-12(1) = x-12(3)

2x-12 = 3x-36

2x-3x = -36+12

-x = - 24

x = 24

So if we substitute the values we get,

Son's age = 24 years

Man's age = 48 years

Hope you understand :)

Step-by-step explanation:

Let the present age of father be ' x ' years and that of the son be ' y ' years. From the first condition ,

From the second condition ,

Substituting the value of x from equation ( i ) in equation ( ii ) :

Solve for y ( age of the son ) :

⟿

⟿

⟿

⟿

Now , Substituting the value of y in equation ( i ) , we get :

⟿

So, the present age of the father is 48 years and that of the son is 24 years.

Hope I helped ! ツ

Have a wonderful day / night ♡

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁