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starfox5454
18.01.2021 •
Mathematics
A marketing research company desires to know the mean consumption of meat per week among males over age 26. They believe that the meat consumption has a mean of 3.7 pounds, and want to construct a 80% confidence interval with a maximum error of 0.09 pounds. Assuming a standard deviation of 1.4 pounds, what is the minimum number of males over age 26 they must include in their sample
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Ответ:
80% confidence interval with Maximum error is
(3.61, 3.79)
Step-by-step explanation:
Explanation
Given the mean of the sample ( x⁻) = 3.7
The maximum error = 0.09
80% confidence interval is determined by
( x⁻ - M.E , x⁻ + M.E)
( 3.7 - 0.09 , 3.7 +0.09)
(3.61 , 3.79)
Final -
80% confidence interval with Maximum error is
(3.61, 3.79)
Ответ:
I think this answer
1.Factors of 27 are {1,3,9,27)
2.Factors of 45 are {1,3,5,9,15,45)
3.Common factors are {1,3,9
the biggest common factor number is the gcf number. So the greatest commen factor 27&45 is 9