A menu offers a choice of 2 salads, 6 main dishes, and 5 desserts. How many different meals consisting of one salad, one main dish, and one dessert are possible?

Answer is 60

Step-by-step explanation:

The possibility of a salad meal is =2

2C1 = 2

The possibility of a main dish = 6

6C1 = 6

The possibility of a dessert is = 5

5C1 = 5

So the total possibility is the multiplication of the three i.e

2*6*5 = 60

The principle applied is the combination principle.

Note that C stands for combination

=40a8

Step-by-step explanation:

=(−8a2)*(−5a6)

=(−8)*a2*(−5)*a6

=((−8)*(−5))*(a2*a6)

=40*a8

=40a8