jb230
01.09.2020 •
Mathematics
a missile is fired with 96% accuracy. Each firing is independent of the other. If four missiles are fired what is the probability only the second one misses
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Ответ:
0.03538944
Step-by-step explanation:
Given, The accuracy of missile = 96%
i.e. The probability that it will hit the shot = 0.96
Probability of missing the shot = 1-0.96= 0.04
Now, each missile is independent of other.
Therefore, the probability only the second one misses = (probability that first will hit the shot) x (probability that second one misses ) x (probability that third will hit the shot)x (probability that fourth will hit the shot)
Thus, the probability only the second one misses is
Hence, the required probability = 0.03538944
Ответ: