A model rocket launched directly upward at a speed of 16 meters per second from a helght of 2 meters . The f(t) = - 4.9t ^ 2 + 16t + 2 models the relationship between the height of the rocket and the time after launch, t. In seconds. Which is the maximum height meters the rocket will reach Round to two decimal places Provide your answer below: meters

f(t) = 15.06 m

Step-by-step explanation:

The relationship between the height of the rocket and the time after launch, t. In seconds is given by :

We need to find the maximum height the rocket will reach the ground.

When it reaches the ground,

f(t) = 0

So,

Maximum height,

f'(t) = 0

Put t = 1.63 in equation (1).

So, the maximum height of the rocket is 15.06 m.

Here, we have to examine the equation of the straight line which is denoted by: y = m x +c where "m" is the slope which represents the steepness and c is the y-intercept

Here, the two linear functions have the same slope "m" and the same y-intercept "c". When both these are the same, the two linear functions are representing the same straight line.

Therefore, Jeremy is correct in his argument.