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gabbie63
13.07.2020 •
Mathematics
A mortar shell is fired with a muzzle speed of 300 ft/sec. Find the angle of elevation of the mortar if the shell strikes a target located 1500 ft away. Round your answer to 2 decimal places.
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Ответ:
Angle of elevation = 4.37°
Step-by-step explanation:
Velocity of the mortar shell = 300ft/sec
Distance covered= 1500ft
Range = U²sin2tita/g
But range= distance
Range = 1500ft
U = velocity
g = acceleration due to gravity
Tita = angle of projection of elevation
1500 = 300²sin(2tita)/9.87
(1500*9.87)/90000= sin2tita
0.1645 = sin2tita
Sin^-1 0.1645 = 2tita
9.4682 = 2tita
total = 9.4682/2
tita = 4.3741°
To two decimal place= 4.37°
Ответ:
The final degree is 90
Step-by-step explanation:
Because every triangle equals up to 180 degrees.