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jstamey757
21.02.2020 •
Mathematics
A motorboat travels 165 kilometers in 3 hours going upstream and 510 kilometers in 6 hours going downstream. What is the rate of the boat in still water and what is the rate of the current?
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Ответ:
Given that,
A motorboat travels 165 kilometers in 3 hours going upstream and 510 kilometers in 6 hours going downstream
Therefore,
Upstream distance = 165 km
Upstream time = 3 hours
Find upstream speed:Thus upstream speed is 55 km per hour
Downstream distance = 510 km
Downstream time = 6 hours
Find downstream speed:Thus downstream speed is 85 km per hour
If the speed of a boat in still water is u km/hr and the speed of the stream is v km/hr, then
Speed downstream = u + v km/hr
Speed upstream = u - v km/hr
Therefore,
u + v = 85 ----- eqn 1
u - v = 55 ----- eqn 2
Solve both
Add them
u + v + u - v = 85 + 55
2u = 140
u = 70
Substitute u = 70 in eqn 1
70 + v = 85
v = 85 - 70
v = 15
Thus rate of the boat in still water is 70 km/hr and rate of the current is 15 km/hr
Ответ:
58 days = (24)(58) = 1392 hours
60 mins = 1 hour
30 mins = 30/60 hour = 1/2 hour
Total hours Keurig takes to complete a full rotation = 1392 + 15 + 1/2 = 1407(1/2) hours.