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Jana1517
24.09.2020 •
Mathematics
A new outdoor recreation center is being built in Hadleyville. The perimeter of the rectangular playing field is 316 yards. The length of the field is 4 yards less than twice its width. What are the dimensions of the playing field?
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Ответ:
Given :
Perimeter of rectangular filed , P = 316 yards.
The length of the field is 4 yards less than twice its width.
To Find :
The dimensions of the playing field.
Solution :
Let, width be x.
So, by given condition length will be 2x - 4.
Perimeter is given by :
P = 2( l + b )
316 = 2( 2x - 4 + x )
3x - 4 = 158
x = 54 yards.
So, the dimensions are 54 yards and 104.
Hence, this is the required solution.
Ответ: