A normal distribution has mean μ and standard deviation σ .An x-value is randomly selected from the distribution. Find P(μ−σ≤x≤μ+ 3σ)
P(μ−σ≤x≤μ+ 3σ)=

The probability that a randomly selected  x-value lies between μ − 2σ and μ is the  shaded area under the normal curve shown.  P(μ − 2σ ≤ x ≤ μ) = 0.135 + 0.34 = 0.475

Step-by-step explanation:

The inverse of  is  and it is a function.======the inverse of  can be found by replacing function notation with y.    turns into  .then we swap x and y.    now we can solve for y to get an explicit equation for the inverse.  subtract 6 from both sides, then divide by 3 to isolate y.      is a function. it is a linear function, a straight line.it will pass the vertical line test.since the inverse is a function, we can replace y with the notation for an inverse function to f(x):