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dmckinnies8
19.05.2021 •
Mathematics
A Parallelogram whose vértices have coordinates r(1,-1) s(6,1) t (8,5) u 3,3 have a shorter diagonal
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Ответ:
The two shortest diagonals seems to be RU and TS. A further explanation is provided below.
Step-by-step explanation:
The given coordinated are:
r = (1, 1)
s = (6, 1)
t = (8, 5)
u = (3, 3)
Now,
The distance between RU will be:
=![\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](/tpl/images/1333/7041/60cfb.png)
On putting the values, we get
=![\sqrt{(3-1)^2+(3+1)^2}](/tpl/images/1333/7041/d1451.png)
=![\sqrt{(2)^2+(4)^2}](/tpl/images/1333/7041/86546.png)
=![\sqrt{4+16}](/tpl/images/1333/7041/d5d1a.png)
=![\sqrt{20}](/tpl/images/1333/7041/2ca86.png)
Ответ: