BigDaddy1220
06.11.2020 •
Mathematics
A particle moves on the circle x2+y2=25 x 2 + y 2 = 25 in the xy x y -plane for time t≥0 t ≥ 0 . At the time when the particle is at the point (3,4) ( 3 , 4 ) , dxdt=6 d x d t = 6 . What is the value of dydt d y d t at this time?
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Ответ:
y + 2x - y = 18
Simplifying
y + 2x + -1y = 18
Reorder the terms:
2x + y + -1y = 18
Combine like terms: y + -1y = 0
2x + 0 = 18
2x = 18
Solving
2x = 18
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Divide each side by '2'.
x = 9
Simplifying
x = 9