A particle travels along the xx-axis such that its velocity is given by v(t)=t^{0.3}\cos\left(2t+3\right).v(t)=t 0.3 cos(2t+3). If the position of the particle is x=3x=3 when t=0,t=0, what is the position of the particle when t=3?t=3? You may use a calculator and round your answer to the nearest thousandth.

Because both diagonals AC and BD are the same length, that means that where they intersect at is the same length(i.e AE and BE). Since those are the same, that means that this triangle should be an isosceles triangle, with at least 2 sides having the same length.