A person has 28 coins, all dimes and quarters, worth $4.60. How many quarters are there? 16
18
12

Remember that a dime is worth 10 cents and a quarter is worth 25 cents and $4.60 is 460 cents.

Let D = the number of dimes and Q = the number of quarters.

Now let's translate the English into math. . .

there are 28 coins in all--> D + Q = 28  so D = 28 - Q

they are worth 460 cents--> 10D + 25Q = 460

Now substitute 28-Q for D--> 10(28-Q) + 25Q = 460

280 - 10Q + 25Q = 460

Combine like term. . .

15Q = 180

Divide both sides by 15--> Q = 12

So D = 16

12

Step-by-step explanation:

D=dimes Q=quarters

D+Q=28 so D=28-Q

460=10D+25Q

substitute 28Q for D

10(28-Q)+25Q=460

280-10Q+25Q=460

combine like terms

15Q=180

divide both sides by 15 so Q= 12 and D=16

(I believe this is the correct answer)

A) children attended=98 b) students attended=60 c)adults attended=49

Step-by-step explanation:

system%28a%2Bc%2Bx=207%2Cc%2Fa=2%2C5c%2B7x%2B12a=1498%29

Simplify and solve the system.

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a%2B2a%2Bx=207

3a%2Bx=207

x=207-3aandc=2a

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The revenue equation can be written in terms of just one variable, a.

10a%2B7%28207-3a%29%2B12a=1498

Solve for a;

use it to find x and c.

FURTHER STEPS

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10a%2B1449-21a%2B12a=1498

a%2B1449=1498

a=98-49

highlight%28a=49 adults

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c=2a

c=2%2A49

highlight%28c=98 children

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x=207-a-c

x=207-49-98

highlight%28x=60 students