blackbetty79
20.03.2020 •
Mathematics
A phone company offers two packages of service. Package A is $35.00 per month with an additional charge of $0.15 per minute for long distance. Package B is $45.00 per month with an additional charge of $0.10 per minute for long distance. How many minutes have to be used for the costs of both plans to be the same?
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Ответ:
200 minutes have to be used for the costs of both plans to be the same.
Step-by-step explanation:
Let x represent the number of minutes that have to be used for the costs of both plans to be the same.
Package A is $35.00 per month with an additional charge of $0.15 per minute for long distance. This means that the cost of using package A for x minutes in a month would be
35 + 0.15x
Package B is $45.00 per month with an additional charge of $0.10 per minute for long distance. This means that the cost of using package A for x minutes in a month would be
45 + 0.1x
For both costs to be the same, it means that
35 + 0.15x = 45 + 0.1x
0.15x - 0.1x = 45 - 35
0.05x = 10
x = 10/0.05
x = 200
Ответ:
an=a1(r)^(n-1)
so
given
a1=4
and a3=36
36=a3=4(r)^(3-1)
36=4(r)^2
9=r^2
3=r
an=4(3)^(n-1)
a6 is
a6=4(3)^(6-1)
a6=4(3)^5
a6=4(243)
a6=972
a6=972